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	* add back exif-terminator and use only for jpeg,png,webp * fix arguments passed to terminateExif() * pull in latest exif-terminator * fix test * update processed img --------- Co-authored-by: tobi <tobi.smethurst@protonmail.com>
		
			
				
	
	
		
			97 lines
		
	
	
	
		
			3.7 KiB
		
	
	
	
		
			Go
		
	
	
	
	
	
			
		
		
	
	
			97 lines
		
	
	
	
		
			3.7 KiB
		
	
	
	
		
			Go
		
	
	
	
	
	
| // Copyright 2017 Google Inc. All rights reserved.
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| //
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| // Licensed under the Apache License, Version 2.0 (the "License");
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| // you may not use this file except in compliance with the License.
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| // You may obtain a copy of the License at
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| //
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| //     http://www.apache.org/licenses/LICENSE-2.0
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| //
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| // Unless required by applicable law or agreed to in writing, software
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| // distributed under the License is distributed on an "AS IS" BASIS,
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| // WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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| // See the License for the specific language governing permissions and
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| // limitations under the License.
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| 
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| package s2
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| 
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| // WedgeRel enumerates the possible relation between two wedges A and B.
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| type WedgeRel int
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| 
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| // Define the different possible relationships between two wedges.
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| //
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| // Given an edge chain (x0, x1, x2), the wedge at x1 is the region to the
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| // left of the edges. More precisely, it is the set of all rays from x1x0
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| // (inclusive) to x1x2 (exclusive) in the *clockwise* direction.
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| const (
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| 	WedgeEquals              WedgeRel = iota // A and B are equal.
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| 	WedgeProperlyContains                    // A is a strict superset of B.
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| 	WedgeIsProperlyContained                 // A is a strict subset of B.
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| 	WedgeProperlyOverlaps                    // A-B, B-A, and A intersect B are non-empty.
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| 	WedgeIsDisjoint                          // A and B are disjoint.
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| )
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| 
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| // WedgeRelation reports the relation between two non-empty wedges
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| // A=(a0, ab1, a2) and B=(b0, ab1, b2).
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| func WedgeRelation(a0, ab1, a2, b0, b2 Point) WedgeRel {
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| 	// There are 6 possible edge orderings at a shared vertex (all
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| 	// of these orderings are circular, i.e. abcd == bcda):
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| 	//
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| 	//  (1) a2 b2 b0 a0: A contains B
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| 	//  (2) a2 a0 b0 b2: B contains A
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| 	//  (3) a2 a0 b2 b0: A and B are disjoint
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| 	//  (4) a2 b0 a0 b2: A and B intersect in one wedge
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| 	//  (5) a2 b2 a0 b0: A and B intersect in one wedge
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| 	//  (6) a2 b0 b2 a0: A and B intersect in two wedges
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| 	//
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| 	// We do not distinguish between 4, 5, and 6.
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| 	// We pay extra attention when some of the edges overlap.  When edges
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| 	// overlap, several of these orderings can be satisfied, and we take
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| 	// the most specific.
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| 	if a0 == b0 && a2 == b2 {
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| 		return WedgeEquals
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| 	}
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| 
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| 	// Cases 1, 2, 5, and 6
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| 	if OrderedCCW(a0, a2, b2, ab1) {
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| 		// The cases with this vertex ordering are 1, 5, and 6,
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| 		if OrderedCCW(b2, b0, a0, ab1) {
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| 			return WedgeProperlyContains
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| 		}
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| 
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| 		// We are in case 5 or 6, or case 2 if a2 == b2.
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| 		if a2 == b2 {
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| 			return WedgeIsProperlyContained
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| 		}
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| 		return WedgeProperlyOverlaps
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| 
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| 	}
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| 	// We are in case 2, 3, or 4.
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| 	if OrderedCCW(a0, b0, b2, ab1) {
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| 		return WedgeIsProperlyContained
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| 	}
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| 
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| 	if OrderedCCW(a0, b0, a2, ab1) {
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| 		return WedgeIsDisjoint
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| 	}
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| 	return WedgeProperlyOverlaps
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| }
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| 
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| // WedgeContains reports whether non-empty wedge A=(a0, ab1, a2) contains B=(b0, ab1, b2).
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| // Equivalent to WedgeRelation == WedgeProperlyContains || WedgeEquals.
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| func WedgeContains(a0, ab1, a2, b0, b2 Point) bool {
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| 	// For A to contain B (where each loop interior is defined to be its left
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| 	// side), the CCW edge order around ab1 must be a2 b2 b0 a0.  We split
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| 	// this test into two parts that test three vertices each.
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| 	return OrderedCCW(a2, b2, b0, ab1) && OrderedCCW(b0, a0, a2, ab1)
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| }
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| 
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| // WedgeIntersects reports whether non-empty wedge A=(a0, ab1, a2) intersects B=(b0, ab1, b2).
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| // Equivalent but faster than WedgeRelation != WedgeIsDisjoint
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| func WedgeIntersects(a0, ab1, a2, b0, b2 Point) bool {
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| 	// For A not to intersect B (where each loop interior is defined to be
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| 	// its left side), the CCW edge order around ab1 must be a0 b2 b0 a2.
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| 	// Note that it's important to write these conditions as negatives
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| 	// (!OrderedCCW(a,b,c,o) rather than Ordered(c,b,a,o)) to get correct
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| 	// results when two vertices are the same.
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| 	return !(OrderedCCW(a0, b2, b0, ab1) && OrderedCCW(b0, a2, a0, ab1))
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| }
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